8c+c^2-20=

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Solution for 8c+c^2-20= equation:


Simplifying
8c + c2 + -20 = 0

Reorder the terms:
-20 + 8c + c2 = 0

Solving
-20 + 8c + c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(-10 + -1c)(2 + -1c) = 0

Subproblem 1

Set the factor '(-10 + -1c)' equal to zero and attempt to solve: Simplifying -10 + -1c = 0 Solving -10 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '10' to each side of the equation. -10 + 10 + -1c = 0 + 10 Combine like terms: -10 + 10 = 0 0 + -1c = 0 + 10 -1c = 0 + 10 Combine like terms: 0 + 10 = 10 -1c = 10 Divide each side by '-1'. c = -10 Simplifying c = -10

Subproblem 2

Set the factor '(2 + -1c)' equal to zero and attempt to solve: Simplifying 2 + -1c = 0 Solving 2 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -1c = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -1c = 0 + -2 -1c = 0 + -2 Combine like terms: 0 + -2 = -2 -1c = -2 Divide each side by '-1'. c = 2 Simplifying c = 2

Solution

c = {-10, 2}

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